Answer:
60º
Step-by-step explanation:
Label the radii OB and OC where AB and AC are tangents. OB and OC are 4.5 cm as they are both radii. Then we can see that OBA and OCA are both right triangles with OBA=OCA=90º. OAB=OAC=30º because the side lengths fit the criteria for a 30-60-90 triangle. OAB+OAC=60º
Answer:
(5a+b)⋅(5a−b)
Step-by-step explanation:
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
52a2 - b2
STEP
2
:
Trying to factor as a Difference of Squares
2.1 Factoring: 25a2-b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 25 is the square of 5
Check : a2 is the square of a1
Check : b2 is the square of b1
Factorization is : (5a + b) • (5a - b)
You just add all the sides together for perimeter
the answer is105
