Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F =
where k=

So , 2.2 =
(
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
Tan(theta)= opposite/ adjacent
tan(35) = opp / 10ft
opp=10 * tan(35)
opp= 7.002 ft tall
C because it’s just it srry if it’s not but I think it is