Answer:
XS is 9 inches long.
Step-by-step explanation:
Given that
YS is the perpendicular bisector of XZ.
Length of XZ = 18 inches
To find:
Length of XS = ?
Solution:
First of all, let us learn about the perpendicular bisector.
Perpendicular bisector of a line <em>AB</em> is a line <em>PQ</em>, which divides the line AB in two equal parts and is at an angle of
with the line AB.
If B is on the line PQ, then
and
![\angle ABP = \angle ABQ = 90^\circ](https://tex.z-dn.net/?f=%5Cangle%20ABP%20%3D%20%5Cangle%20ABQ%20%3D%2090%5E%5Ccirc)
Applying the above property in our given question.
Kindly refer to the attached image for the given dimensions.
S is on the line XZ.
![XS = SZ = \frac{XY}{2} = \dfrac{18}{2} \\\Rightarrow \bold{XS = 9\ inches}](https://tex.z-dn.net/?f=XS%20%3D%20SZ%20%3D%20%5Cfrac%7BXY%7D%7B2%7D%20%3D%20%5Cdfrac%7B18%7D%7B2%7D%20%5C%5C%5CRightarrow%20%5Cbold%7BXS%20%3D%209%5C%20inches%7D)
So, the answer is XS is 9 inches long.
Answer:
c
Step-by-step explanation:
if 3500 employees work at the firm, the you minus the total amount of employees taking either a car or the train from 3500 (3500-2300 = 1200)
Answer:
2 or 6
Step-by-step explanation:
i would prefer talk about either some math, or some new science updates, if you ever need to learn anything about cool science i always go to Mark Rob -er on you tube
The graphical representation is give in image
Answer: 2500 years
Step-by-step explanation:
I'm not quite sure if I'm doing this right myself but I'll give it a shot.
We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.
![A(t)=A_{0}(1/2)^t^/^h](https://tex.z-dn.net/?f=A%28t%29%3DA_%7B0%7D%281%2F2%29%5Et%5E%2F%5Eh)
We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For
let's just assume that there are 100 original atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.
![74=100(1/2)^t^/^5^7^3^0](https://tex.z-dn.net/?f=74%3D100%281%2F2%29%5Et%5E%2F%5E5%5E7%5E3%5E0)
Now, solve. First, divide by 100.
![0.74=(0.5)^t^/^5^7^3^0](https://tex.z-dn.net/?f=0.74%3D%280.5%29%5Et%5E%2F%5E5%5E7%5E3%5E0)
Take the log of everything
![log(0.74)=\frac{t}{5730} log(0.5)](https://tex.z-dn.net/?f=log%280.74%29%3D%5Cfrac%7Bt%7D%7B5730%7D%20log%280.5%29)
Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get
![5730\frac{log(0.74)}{log(0.5)} =t](https://tex.z-dn.net/?f=5730%5Cfrac%7Blog%280.74%29%7D%7Blog%280.5%29%7D%20%3Dt)
Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.
Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.