Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
The answer is choice 2 and 3, that is "The quotient has a final decimal and the whole number is less than 11".
Step-by-step explanation:
The product of a ratio: amount (r) over other(s) (variance from 0) becomes mandatory to note this quotient and in the following case Thus q is = 0.0882352941.

It wasn't a repeating decimal, however a final decimal, so it's got an end.
Its quotient may be less than 11 in total.
Numbers of W = {0,1,2, ...} and 0 < 11 are provided for this entire series of data therefore It's real .
Answer:
53/10 > 38/10
Step-by-step explanation: