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Marianna [84]
3 years ago
7

15 points!!!!

Physics
1 answer:
Savatey [412]3 years ago
4 0

Answer: True                                I'm not very good at Chemistry, I'm sorry if it's wrong, I'm sure it is true though. I hope it helped!!

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What is the pendulum length whose period is 2.0s ?
Mashutka [201]
Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24mT=2 \pi   \sqrt{\frac{L}{g}} \\
 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi }  = \frac{L}{g} \\
 \frac{T^2}{2 \pi }*g=L\\
L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m

7 0
3 years ago
What did B.F. skinnier believe drove ones behaviors
Nastasia [14]
He thought that behavior is determined by its consequences.
5 0
3 years ago
A primary advantage of composite materials is: (choose all that apply). 1.) high strength 2.) low weight 3.) ease of constructio
icang [17]

Answer:

primary advantage of composite material are high strength, low weight, corrosion resistance

Explanation:

The primary advantage of composite material is

1) high strength - they are stronger in strength than commanly used material like steel and aluminium.

2)low weight - lighter than most of the material like woods and others metals

3) corrosion resistance - it resist extreme condition of weather and can be good place where handling of chemicals takes place.

4 0
3 years ago
The Voyager 1 spacecraft, shown below, completed its space exploration mission in 1980 and has since been traveling away from Ea
aleksklad [387]
I think b hope this helps
4 0
3 years ago
Read 2 more answers
Un protón se acelera por una diferencia de potencial de 2.6k V y se dirige a una región donde existe un campo magnético uniforme
Bond [772]

Answer:

5.08*10^{-13}N

Explanation:

With this information we can calculate the velocity of the proton by taking into account the kinetic energy of the proton:

qV=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(1.6*10^{-19}C)(2.6*10^3V)}{1.67*10^{-27}kg}}=705835.3m/s

The magnitude of the magnetic force will be:

F=qvB=(1.6*10^{-19}C)(705835.3m/s)(4.5T)=5.08*10^{-13}N

hope this helps!

7 0
3 years ago
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