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3 years ago

9

How does wavelength and frequency affect the speed?

1 answer:

kvasek [131]3 years ago

3 0

Rather, an alteration in wavelength affects the frequency in an inverse manner. A doubling of the wavelength results in a halving of the frequency; yet the wave speed is not changed.

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An electric bell is kept under a bell jar in which a vacuum has been created. Slowly air is introduced in to the jar. What will

Aleks [24]

A. Increase until it reaches it's maximum. Sound travels through air and as the amount of air in the jar increases, the loudness or amplitude of the bell increases until it reaches it's maximum at normal air pressure.

8 0

3 years ago

Read 2 more answers

An astronaut goes out for a space-walk at a distance above the earth equal to the radius of the earth. What is her acceleration

Lera25 [3.4K]

Answer: $\frac{g}{4}$

Explanation:

Let m be the mass of Astronaut

M=mass of earth

G=Gravitational constant

R=radius of Earth

Force Exerted by Earth on Astronaut

$F=\frac{GmM}{R^2}$

acceleration due to gravity is $=\frac{F}{m}=g$

$g=\frac{GM}{R^2}$

When it is at $r=2R$

$g'=\frac{GM}{(2R)^2}$

$g'=\frac{GM}{4R^2}=\frac{g}{4}$

7 0

3 years ago

Derive mean in science <br>

eduard

Explanation:

derive its name from a Native American word meaning wild onion

6 0

3 years ago

Ethan is using a machine to mix cement. The work input is 10 and the work output is 8. What is the efficiency of the

Arturiano [62]

Efficiency or $\eta$ is calculated by formula: $\eta=\frac{W_{output}}{W_{input}}$ where $\eta\leq1$ also efficiency has no unit.

Now put in the data and calculate the efficiency.

$\eta=\frac{8}{10}=\boxed{0.8}$

The efficiency of the machine is 0.8

If you want to get percentage just multiply by 100 and you get 80%

Hope this helps.

r3t40

4 0

3 years ago

Find the weight required to stretch a steel road by 2 mm, if the length of the road is 2 m and diameter 4 mm. Y= 200 GPa and g -

svetlana [45]

Answer:

Option D is the correct answer.

Explanation:

We equation for elongation

$\Delta L=\frac{PL}{AE}$

Here we need to find weight required,

We need to stretch a steel road by 2 mm, that is ΔL = 2mm = 0.002 m

$A=\frac{\pi d^2}{4}=\frac{\pi ({4\times 10^{-3}})^2}{4}=1.26\times 10^{-5}m^2$

E = 200GPa = 2 x 10¹¹ N/m²

L=2m

Substituting

$0.002=\frac{P\times 2}{1.26\times 10^{-5}\times 2\times 10^{11}}\\\\P=2520N=256.4kg$

Option D is the correct answer.

6 0

3 years ago