Answer:
9 and 11
Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.
n(n + 2) = 99
Solve for n.
n2 + 2n - 99 = 0
(n + 11)(n - 9) = 0 ⇒
Two solutions:
n = -11
n + 2 = -9
and
n = 9
n + 2 = 11
Test the answers.
B > -21 is i think you answer.
Part a)
Answer: 5*sqrt(2pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi
Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"
============================================================
Part b)
Answer: 3*sqrt(3pi)/pi
-----------------------
Work Shown:
r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi
Note: the same issue comes up as before in part a)
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Part c)
Answer: sqrt(19pi)/pi
-----------------------
Work Shown:
r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
Answer:
13.5
Step-by-step explanation:
150% × 9 =
(150 ÷ 100) × 9 =
(150 × 9) ÷ 100 =
1,350 ÷ 100 =
13.5
My proof :
If 150% × 9 = 13.5 =>
Divide 13.5 by 9...
... And see if we get as a result: 150%.
