Answer:
3.5 Oz of chocolate
Step-by-step explanation:
1.6 lb of cookie dough is made from chocolate of 8 Oz
1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate
Therefore
7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/
Answer:
your answer is for sure D but I think C is also the answer
Step-by-step explanation:
Additive relationship are two quantities can be expressed as related to each other through addition. It can be written as y = x + a, where y is related to x through the addition of a constant, a. The value for a may be positive or negative.
Answer:
see explanation
Step-by-step explanation:
To show f and g are inverses we require to show that
f(g(x)) = x and g(f(x)) = x
f(g(x))
= f(6x - 4)
= 
= 
= x
-----------------------------------------------------------------------------
g(f(x))
= g(
)
= ( 6 × ) - 4
= x + 4 - 4 = x
-------------------------------------------------
Hence f and g are inverses
To solve this, I would just find what two adult tickets and one child ticket wold be worth.
To find that, just do:
5.20 + 9.90 * 2, which makes 25.
So now you just find how many 25s are in 900, or 36.
So 36 children's tickets were sold that day.
Hope I helped :)
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18
15/30: 5/10 OR 1/2
45/60: 8/12 OR 4/6
Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number.
5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8.
2/5 and 1/2: 2/5 and 2.5/5
9/9 and 5/7: 9/9 and ~5.7/9
Rewrite each in simple form: Find greatest common factor and divide.
9/54: 1/6
20/40: 1/2
100/110: 10/11
Are these fractions equivalent?
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole.
In what situation can you use multiplication to find equivalent fractions?
I'm sorry but I do not understand this question.
</span>Source(s):<span>I hope I helped, seeing as I have graduated with a math degree.</span>
