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sergejj [24]
4 years ago
6

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.

After 6 hours of burning, a candle has a height of 24.6 centimeters. After 21 hours of burning, its height is 18.6 centimeters. What is the height of the candle after 9 hours?
Mathematics
1 answer:
SOVA2 [1]4 years ago
8 0

Given: After 6 hours of burning, a candle has a height of 24.6 centimeters. After 21 hours of burning, its height is 18.6 centimeters.

Solution: We could write coordinates for number of hours and height of the candle (hours, height) for the above data as

(6,24.6) and (21,18.6).

In order to find the linear function, we need to find the slope between those two coordinates.

Slope would represent the rate at which length of candle is decreasing.

Let is find slope between those two coordinates now.

We know, slope formula

m= \frac{y2-y1}{x2-x1}

We have (x1,y1)=(6,24.6)  and (x2,y2) = (21,18.6).

Plugging values of x1,y1,x2 and y2 in slope formula, we get

m=\frac{18.6-24.6}{21-6}=\frac{-6}{15}

Simplfying fraction -6/15 into simplest form, we get

-2/5.

So, the slope m=-2/5.

In decimal form -2/5 = -0.4.

Applying point-slope form of the linear equation

y-y1 = m(x-x1)

y- 24.6= -0.4(x-6).

Distributing -0.4 over (x-6), we get -0.4*x -0.4*-6 = -0.4x +2.4

y-24.6 = -0.4x +2.4

Adding 24.6 on both sides, we get

y-24.6+24.6 = -0.4x +2.4+24.6

y = -0.4x + 27.

Now, we need to find height of the candle after 9 hours.

x represents number of hours there.

Plugging x=9 in above function we got,

y = -0.4(9) + 27

y= -3.6 +27

y =23.4

Therefore, 23.4 centimeters is the height of the candle after 9 hours.


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Answer:

About 3891 people saw that movie.

Step-by-step explanation:

Day 1: 985 people

Day 2: (985*8)/10 (20% gone) = 788

Day 3: (788*8)/10 (20% gone) = 630.4

Day 4: (630.4*8)/10 (20% gone) = 504.32

Day 5: (504.32*8)/10 (20% gone) = 403.456

Day 6: (403.456*8)/10 (20% gone) = 322.7648

Day 7: (322.7648*8)/10 (20% gone) = 258.21184

Adding this up:

985+788+630.4+504.32+403.456+322.7648+258.21184=

985+788+630+504+403+323+258=3891

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A company buys pens at the rate of $7.50 per box for the first 10 boxes, $5.50 per box for the next 10 boxes, and $4.50 per box
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Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
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Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
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