Find the similarity ratio of a cube with volume 729 m3 to a cube with volume 3,375 m3.iR²

2 answers:

8 0

The similarity ratio of a cube with volume 729 m3 to a cube with a volume of 3,375 m3.iR² is 3:5. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you, and if you would like, feel free to ask another question.

Vesna [10]3 years ago

5 0

Answer: The similarity ratio of the two cubes is 9 : 15.

Step-by-step explanation: We are to find the similarity ratio of a cube with volume 729 m³ to a cube with volume 3375 m³.

We know that if two solids are similar, then ratio of their volumes is equal to the cube of the ratio of their corresponding sides.

Let, 'a' m and 'b' m be the lengths of two corresponding sides of the cubes with volumes 729 m³ and 3375 m³ respectively.

Then, we must have

$729:3375=a^3:b^3\\\\\\\Rightarrow \dfrac{a^3}{b^3}=\dfrac{729}{3375}\\\\\\\Rightarrow \left(\dfrac{a}{b}\right)^3=\left(\dfrac{9}{15}\right)^3\\\\\\\Rightarrow \dfrac{a}{b}=\dfrac{9}{15}\\\\\\\Rightarrow a:b=9:15.$

Thus, the similarity ratio of the two cubes is 9 : 15.

You might be interested in

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

3 years ago

What is the period of the cosecant function graphed below?

telo118 [61]

Step-by-step explanation: The cosecant function is graphed in the given figure. we are to find the period of the function.
The period of a function is the distance travelled by the curve of the function in one complete revolution.
We can see that in the given figure, the distance between two consecutive points is given by

Therefore, the period of the cosecant function is
Thus, the correct option is (B) \pi.

4 0

2 years ago

Help ASAP PLEASEE!!!!!!!!

olga_2 [115]

Answer:

2B + F + 8

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

20. What is the slope of the line containing the points (3,8)

Lerok [7]