Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

Mathematics

2 answers:

Rainbow [258]3 years ago

7 0

Answer:

z=108

Step-by-step explanation:

z÷12=9

x12 x12

z=108

vredina [299]3 years ago

3 0

Answer: z= 108

Explanation:

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Jim is running on a trail that is 5/4 of a mile long. So far he has run 2/3 of the trail. How many miles has he run so far?

Advocard [28]

You have to subtract 5/4 by 2/3 but in order to do that you must find a common denominator or least common multiple so the least common denominator of 4 and 3 is 12 so you have to multiply 4 by 3 and three by 4 to make both denominators 12 but you have to do the same thing on the top as you did the bottom so: 5/4*3= 15/12 and 2/3*4=8/12 Then 15/12-8/12 is 7/12 so Jim has to run 7/12 more

7 0

3 years ago

Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t

hram777 [196]

Answer:

a. $\mu=15$

b. $\mu=7.8586 \ and \ \mu=22.1414$

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

$P(X=k)=C_k^n.p^k.(1-p)^{n-k}$

Let n be the number of trials, $n=100$

and p be the probability of success, $p=15\%$

The mean of a binomial distribution is the probability x sample size.

$\mu=np=100\times0.15=15$

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as: $\sigma=\sqrt npq\\q=1-p$

Therefore, $\sigma=\sqrt(100\times0.015\times0.85)=3.5707$

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

$sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414$

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c. $x=45$ is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.