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4 years ago

Comeplete this homework assignment and do it on a spearate sheet of paper.

Mathematics

1 answer:

andrew11 [14]4 years ago

7 0

Answer:

Where is it ?

Step-by-step explanation:

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(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers

Y=3x+4 y=-2x-1 mathaaaaa

valentinak56 [21]

Answer:

the answer is x=−1 and y=1

Step-by-step explanation:

hoped I helped:)

7 0

3 years ago

Can someone please help me! Big ideas 8.4 number 20

Harlamova29_29 [7]

<u>Answer:</u> The perimeter is about 20.26 units

<u>Step-by-step explanation:</u>

To calculate the distance between the points, we use the formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where,

d = distance

$x_2\text{ and }x_1$ are the coordinates of the points on x-axis

$y_2\text{ and }y_1$ are the coordinates of the points on y-axis

For the given points:

B(0,3), C(4,-1), E(2,-3) and F(-2,1)

Calculating the distance BC:

$x_2=4\\x_1=0\\y_2=-1\\y_1=3$

Putting values in above equation, we get:

$BC=\sqrt{(4-(0))^2+(-1-3)^2}\\\\d=\sqrt{16+16}=5.66units$

Calculating the distance CE:

$x_2=2\\x_1=4\\y_2=-3\\y_1=-1$

Putting values in above equation, we get:

$CE=\sqrt{(2-(4))^2+(-3-(-1))^2}\\\\d=\sqrt{36+4}=4.47units$

To calculate the perimeter of a rectangle, we use the equation:

$Perimeter=2(l+b)$ ....(1)

where,

l = length of the rectangle = BC = 5.66 units

b = breadth of the rectangle = CE = 4.47 units

Putting values in equation 1, we get:

$Perimeter=2(5.66+4.47)\\\\Perimeter=20.26 units$

Hence, the perimeter is about 20.26 units

7 0

3 years ago

Deon earns $91 washing 7 dogs. At this rate, how many dogs did Deon wash to earn $117?

mamaluj [8]

$91/ 7 = $13 per dog
$117/$13 = 9 dogs
He washed 9 dogs

4 0

3 years ago

I need help this plzz

guapka [62]

#1 second line: x-y=-3
x=y-3(isolating x to prepare for substitution)(what x is equivalent to)
get back to the first line
x+y=5
(y-3)+y=5(substituting the value of x of the first line with the value of x at the second line)(It is a process to find the intersection between the two lines(line#1 and line#2 are two linear functions)
2y-3=5(simplify)
2y=8(simplify)
y=4(simplify)
line#1 x+y=5
x+(4)=5(plug the value of y back into either line#1 or line#2 will work)(plugging in the y value of the point of intersection to solve for the x value of the point of intersection)
x=1(solve)
the two linear lines intersect at the point(1(x coordinate), 4(y coordinate))(1,4)

#2 (line#1) y=3x-1
(line#2) 2x+y=14
2x+(3x-1)=14
5x-1=14
5x=15
x=3
y=3(3)-1
y=9-1
y=8
(3,8)

#3 line#1 2x+3y=8
line#2 6x+9y=24
2x=8-3y
x=(8-3y)/2
6((8-3y)/2)+9y=24
24-9y+9y=24
24=24
(those two lines are on top of yeach other/the same line)
any point on the line

#4 line#1 3x-4y=12
line#2 y=3/4x-4
3x-4(3/4x-4)=12
3x-3x+16=12
16=12
parallel lines: lines with same slope and different y-intercept
No solution/they never intercept each other

I hope it is helpful, if you have any question, I will answer ASAP

8 0

3 years ago