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Over [174]
3 years ago
7

A (-5,3)

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

- 3/4

Step-by-step explanation:

m = difference of y / difference of x = (3 - (-3)) / (-5 -3) = 6 / -8 = - 3 / 4

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Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=
Nezavi [6.7K]

Given:

The system of equations is

y=2x-5

2y-4x=?

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

y=2x-5

2y-4x=k

Taking all the terms on the left side, the given equations can be rewritten as

-2x+y+5=0

-4x+2y-k=0

The system of equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 have infinitely many solutions if

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

We have,

a_1=-2,b_1=1,c_1=5

a_2=-4,b_2=2,c_2=-k

Now,

\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{5}{-k}

On cross multiplication, we get

-k=10

k=-10

Therefore, the missing value is -10.

6 0
3 years ago
7x(3x2) and (7x3)x2​
Elis [28]

Answer:

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Solve this system of equations using the ELIMINATION method.
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4 0
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Read 2 more answers
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laiz [17]

Answer:

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Step-by-step explanation:

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the equation equals to 25 so you need to find what x is by subtracting the other value

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6 0
3 years ago
(2x-6)(x+11)<br><br>a)x2-66x+16<br><br>b)x2+16x+11<br><br>c)2x2+16x-66<br><br>d)2x2+11x-66
natka813 [3]
The answer to your math problem is C. The reason being is 2x times x is 2x^2 and 2x times 11 is 22x. So you first part of the problem looks like 2x^2+22. Then -6 times x is -6x and -6 times 11 is -66. So now the problem is 2x^2+22x-6x-66. So your answer after solving it is 2x^2+16x-66.
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