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Monica [59]
3 years ago
12

1. If a rectangular prism with a length of 12 feet and a width of 9 feet has a volume of 1836

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

17 ft

Step-by-step explanation:

1836 = 9 * 12 * h

1836/9*12 = 17

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Using the segment addition postulate, which is true?
marusya05 [52]

Answer:

D

Step-by-step explanation:

For the segment addition postulate, two segments added together have to equal the third segment. In other words, if we added them together, the sum should be the first letter of the first line and the second letter of the second line.

BC + CD = BD

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I did 4 more problems than manuel if I dod p problems write an expression for how many manuel did
Pavlova-9 [17]
He did2.1less problems then u
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4 years ago
A film start at 7:15and finished at 9:30pm.How long is the film?
Mrac [35]

Answer:

2 hours and 15 minutes

Step-by-step explanation:

6 0
2 years ago
Plz help! read the instructions and write a proper answer and if you don't i will report you! And the first one to answer right
ahrayia [7]

Answer:

1 = 0.61, 2 = 1.13

Step-by-step explanation:

The first is 25 + 25 + 10 + 1. This is 61 cents which is 0.61 of 1 dollar. The second is 100 + 10 + 1 + 1 + 1. This is equal to 113, 0r 1.13

BRAINLIEST PLEASE

3 0
2 years ago
In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on
abruzzese [7]

Answer:

(a) P(Y'|M)\approx 0.3297

(b) P(Y|M')\approx 0.8323

(c) P(Y'|M')\approx 0.1323

Step-by-step explanation:

Given table is

                Yes      No      Don't Know      Total

Men          162      92             25               279

Women      258    41              11               310

Total          420    133            36                589

According the the conditional probability, if A and B are two event then

P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}

P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}

P(Y'|M)=\frac{92}{279}

P(Y'|M)=0.329749103943

P(Y'|M)\approx 0.3297

(b)

P(Y|M')=\frac{P(Y\cap M')}{P(M')}

P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}

P(Y|M')=\frac{258}{310}

P(Y|M')=0.832258064516

P(Y|M')\approx 0.8323

(c)

P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}

P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}

P(Y'|M')=\frac{41}{310}

P(Y'|M')=0.132258064516

P(Y'|M')\approx 0.1323

5 0
3 years ago
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