Complete question :
Suppose someone gives you 8 to 2 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win $8 if you succeed and you lose $2 if you fail. What is the expected value of this game to you? What can you expect if you play 100 times.
Answer:
$0.5 ; win $50 with 100 rolls
Step-by-step explanation:
From a roll of two fair dice; probability of obtaining an even number :
Even numbers = (2, 4, 6) = 3
P = 3 /6 = 1 /2
For 2 fair dice ; probability of rolling two even numbers : independent event.
1/2 * 1/2 = 1/4
Hence, p(success) = 1/4 ; P(failure) = 1 - 1/4 = 3/4
Probability table
Winning = $8 or loss = - $2
X : ____ 8 ______ - 2
P(x) __ 1/4 ______ 3/4
Expected value : E(x) = ΣX*P(x)
E(x) = (8 * 1/4) + (-2 * 3/4)
E(x) = 2 - 1.5
E(x) = $0.5
Since expected value is positive, the expect to win
If played 100 times;
Expected value = 100 * $0.5 = $50
The slope of the line would be positive 5/1 instead of positive 3/1. the y-intercept stays the same.
Answer:
£29.6
Step-by-step explanation:
37/5=7.4
37-7.4=29.6
Answer:
Step-by-step explanation:
Method 1:
First do the operation inside parenthesis
2*(4-3) = 2*1 = 2
Method 2:
Use distributive property: a*(b +c) = a*b + a*c
2*(4-3) = 2*4 - 2*3
= 8 - 6
= 2
Answer:
a) ok, heres what u graph, and ur ordered pairs
graph the following points:
(0,0) (1,5) (2,10) (3,15) (4,20) (5,25) (6,30) (7,35), and so on
b) One of the ordered pairs I can use is (1,5). This is beacuse the ordered pair explains that for every video game (x), 5 will be the cost (y).
