Which line of music shows a reflection?

5 - 3(6 - 2y)

saul85 [17]

Answer:

6y - 13

Step-by-step explanation:

5 - 3(6 - 2y)

Distribute;

5 - 18 + 6y

-13 + 6y <em>OR</em> 6y - 13

6 0

3 years ago

Read 2 more answers

Which statement about an input/output table is true?

GREYUIT [131]

The answer is c because the input values do not have to be consecutive, the output values can be decimals and fractions, and the output values are not always increasing as they go on, sometimes they decrease. for example, look at exponential decay and exponential growth. hope this helped (;

4 0

3 years ago

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You have to solve the problems starting at the "begin" and make your way up to the "end". The correct answer is one of the probl

Thepotemich [5.8K]

Begin
3x-4=14
3x=18
x=6

.5n=1.25
n=2.5

x+1=2x-2
x+3=2x
3=x

x+3=10
x=7

6x-13=-11
6x=2
x=1/3

p=4-p
2p=4
p=2

End

6 0

2 years ago

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How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago

Pentagon CDEFG is shown on the coordinate plane. Pentagon CDEFG is translated 7 units up and 5 units left, resulting in C'D'E'F'

Sati [7]

Answer:

The length of line segment FG is equal to the length of F'G'

The perimeter of pentagon CDEFG is equal to the perimeter of pentagon C'D'E'F'G.

Step-by-step explanation:

Given

CDEFG and C'D'E'F'G

Translation: 7 units up and 5 units left

Solving (a): Segment FG and F'G'

When a shape is translated, the resulting image will have the same lengths as the original image (i.e, translation does not change measurements)

Hence:

$FG = F'G'$

Solving (b): Perimeter CDEFG and C'D'EF'G'

In (a), we established that lengths do not change during translation;

Hence:

The perimeter of the CDEFG and C'D'EF'G' will remain the same

3 0

3 years ago

Which line of music shows a reflection?​

Which line of music shows a reflection?