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gregori [183]
3 years ago
9

Consider a hypothetical microprocessor generating 16-bit addresses with 16-bit data accesses (i.e. each access retrieves 16 bits

for each address). provide your answers in decimal.
a. what is the maximum memory address space (number of addresses) that the processor can access directly?
b. what is the maximum memory capacity (in bytes) for this microprocessor?
c. what is the last memory address that the cpu can access?
Computers and Technology
1 answer:
Vlad [161]3 years ago
8 0
A. number of addresses is 65536
b. memory capacity is 128 kbytes or 131072 bytes
c. The last memory address is FFFF which is 65535

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Write a program that uses nested loop or for statements to display Pattern A below, followed by an empty line and then another s
JulsSmile [24]

Answer:

public class Pyramid {

   public static void main(String[] args) {

             int h = 7;

       System.out.println("Pattern A");

               for(int i = 1; i <= h; ++i)

               {

                   for(int j = 1; j <= i; ++j) {

                       System.out.print("+");

                   }

                   System.out.println();

               }

       System.out.println();

       System.out.println("Pattern B");

               for (int i = 1; i<=h; ++i)

               {

                 for(int j = h; j >=i; --j){

                     System.out.print("+");

                 }

                   System.out.println();

               }

           }

       }

Explanation:

  • The trick in this code is using a nested for loop
  • The outer for loop runs from i = 0 to the heigth of the triangle (in this case 7)
  • The inner for loop which prints the (+) sign runs from j = 0 to j<=i
  • It prints the + using the print() function and not println()
  • In the pattern B the loop is reversed to start from  i = height
8 0
3 years ago
A hub transmits all incoming messages to all of its ports except the port where the messages came in. A switch usually sends mes
leonid [27]

Answer:

MAC Addresses (Destination and Source MAC address)

Explanation:

A switch has 3 primary functions:

  • Forward frames
  • Learn addresses
  • Avoid loops

An Ethernet frame has the header, data and trailer and there are two specific fields in the header that helps the switch to know where to send data in future transmissions.

  • destination MAC address
  • source MAC address

every Ethernet frame has this and when the frame hits a switch or any device, any device can look at it ( an Ethernet frame ) and know where it is suppose to go and where it came from.

Every switch has a MAC address table where it stores MAC addresses of different computers on the network.

Example:

When a PC1 sends a frame to PC2 through a switch, the switch looks at the header of the Ethernet frame for the source mac address and adds the source MAC address to its MAC address table and also the port that it came through.

simply put:

A switch looks at the source MAC address to see if it knows it already, if it does. Great! no need to add it again to it's address table.

If it doesn't, it adds it's source address and the port that the frame came from.

This basically how the switch populates its MAC address table.

3 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPPP What should you always disconnect before installing hardware inside a computer’s case?
Ad libitum [116K]

Answer:

a) all cabling hope it helps

3 0
2 years ago
Explain how loops can be utilized in list processing. Please provide Python examples in your response.
Dominik [7]

Answer:

data = [0,1,2,3,4]

for i in range(4):

   print(data[i])

   i+=1

Explanation:

Loops can be utilized in a listing process by looping back to a list with a variable while the loop increases that variable to give a different response from the list.

8 0
2 years ago
Convert the following four unsigned binary numbers to decimal and show your work:
Ber [7]

Answer:

23 ,21,10,63,13

Explanation:

We have to convert binary to decimal

10111 corresponding decimal number is

1\times 2^4+0\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=23

10101 corresponding decimal number is

1\times 2^4+0\times 2^3+1\times 2^2+0\times 2^1+1\times 2^0==21

01010 corresponding decimal number is

0\times 2^4+1\times 2^3+0\times 2^2+1\times 2^1+0\times 2^0=10

111111 corresponding decimal number is

1\times 2^5+1\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=63

001111 corresponding decimal number is

0\times 2^5+0\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=13

7 0
3 years ago
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