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Bad White [126]
3 years ago
12

Solve the equation. 20 = –d + 16

Mathematics
2 answers:
tia_tia [17]3 years ago
7 0

Answer:

–4

Step-by-step explanation:

My name is Ann [436]3 years ago
5 0

Answer:

<h2>d = -4</h2>

Step-by-step explanation:

20 = -d + 16          <em>subtract 16 from both sides</em>

20 - 16 = -d + 16 - 16

4 = -d               <em>change the signs</em>

-4 = d ⇒ d = -4

You might be interested in
there are 7 boys and girls in a club. How many different ways to form a queue starting with a girl after each girl?
Soloha48 [4]

Answer:

7 girls can go in the first place, 6 in the second, etc.

7! ways is the number of ways to arrange the girls.

likewise the boys can be arranged in 7! ways

The total number of ways becomes 7! * 7!

7! * 7! = 25,401 600 ways

8 0
2 years ago
WILL GIVE BRAINLIEST find the value of r (-4,8), (r,12), m=4/3 (show your work pls)
OLEGan [10]

Answer:

r = 13

Step-by-step explanation:

The first step is to find b from y=mx=b using m=4/3 and (-4,8)

8=\frac{4}{3}(-4)+b

After solving the equation, b will equal -16/3 making the final equation be

y=\frac{4}{3} x-\frac{16}{3}

Using the equation, you can solve for r.

12=\frac{4}{3} x-\frac{16}{3}

This will bring the answer being r = 13

7 0
3 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
If three 2-liter sodas cost $14, then how much do five 2-liter sodas cost?
Roman55 [17]

Answer:

23.3

Step-by-step explanation:

6 0
3 years ago
Plz explain.
slega [8]
Idk, why does the world need problems like this, not like everyone is going to grow up to be a math teacher.
8 0
3 years ago
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