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3 years ago

What fraction of an hour is 48 minuets

Mathematics

2 answers:

pashok25 [27]3 years ago

7 0

Answer:

48/60

Step-by-step explanation:

There are 60 minutes in an hour.

Therefore, 48 minutes is 48/60 of an hour.

48/60 simplified is 4/5

Goshia [24]3 years ago

4 0

Answer:

48/60

Step-by-step explanation:

48/60 is 48 minutes of an hour.

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2(x-3)=3/4(8x-12)<br> step by step please

Umnica [9.8K]

Answer:

$x = \frac{3}{4}$

Step-by-step explanation:

$2(x-3)=\frac{3}{4} (8x-12)$

$2x-6 = \frac{3}{4}8x- \frac{3}{4} 12$

$2x-6 = 6x - 9$

$-6+9 = 6x - 2x$

$3 = 4x$

$x = \frac{3}{4}$

7 0

3 years ago

Jasmine runs 13kilometers and 76 minutes. how long woukd it take to run 1 kilometers

k0ka [10]

Answer:

It would take her 5.85 minutes to run 1 kilometer.

Step-by-step explanation:

76/13= 5.846

5 0

3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

Ram is 3 times old as his son and the sum of their age is 48.how old is each?

stich3 [128]

Answer:

12 and 36

Step-by-step explanation:

x+3x=48

4x=48

divide by 4

x=12

48-12=36

6 0

3 years ago

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MAVERICK [17]

Answer: its A

Step-by-step explanation:

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3 years ago

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