12xy i think lol :) hope that helps a bit
<em>IMPORTANT THIGNS TO REMEMBER:</em>
- Has 20 lb. dog food!
- Gives dog 1 3/5 everyday!
- Find how much eaten after 2 days!
- Find how much is left!
<em>ANSWER:</em>
Dog has eaten 3 1/5 after 2 days!
There is 16 4/5 left in bag!
<em>EXPLANATION:</em>
Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5
Which would give you 3 1/5
So, the dog has eaten 3 1/5 lb. of dog food in 2 days.
However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.
Meaning there is 16 4/5 lb. left in the bag of dog food!
Answer:
15ft........
Step-by-step explanation:
it is fifteen feet
The average rate of change for a function f(x) at two different values of x can be calculated by the following formula:

We are to find the find the average rate of change of given function over the range [1,6], so,

Using the values in above formula, we get:

Thus the average rate of change for f(x) = -ln(x) for the interval [1,6] is given by the above expression