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GaryK [48]
3 years ago
9

SOMEBODY PLZ!! ITS THE LAST DAY I DONT WANNA FAIL :*(

Mathematics
1 answer:
spayn [35]3 years ago
8 0
Part A. Lest fin the zeros of our function first: 
f(x)=-x^2-7x+30
Step 1. Set the right side of the function equal to 0:
0=-x^2-7x+30
-x^2-7x+30=0
Step 2. Multiply both sides of the equation by -1
(-1)(-x^2-7x+30)=0(-1)
x^2+7x-30=0
Step 3. Factor the left side: 
(x+10)(x-3)=0
Step 4. Set each factor equal to 0 and solve for x:
x+10=0 and x-3=0
x=-10 and x=3
Since distances can't be negative, the zero of our function is x=3.
<span>We can conclude that the zero </span>x=3 represents that when the horizontal distance of the diver is 3 ft, he is is in the surface of the pool. In other words, his vertical distance is zero. 

Part B. To factor our quadratic equation 9x^2+3x-2=0, we are going to use the method for simple cases because a \neq 0:
Step 1. Find tow numbers whose product is ac and its sum is b:
We know form our quadratic that a=9, b=3, and c=-2, so ac=9(-2)=-18.
We want tow numbers that multiply together to make -18, and add up to 3.
Those number are 6 and -3. (6)(-3)=-18 and 6-3=3
Step 2. Rewrite the middle term 3x using those numbers:
9x^2+6x-3x-2=0
Step 3. Factor the expression:
(9x^2+6x)-(3x+2)=0
3x(3x+2)-(3x+2)=0
(3x+2)(3x-1)=0







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Check
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