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2 years ago

What conclusion can be based on the given statement?

Mathematics

2 answers:

Inessa [10]2 years ago

8 0

Answer:

The option B. q = 43.0 is correct

Step-by-step explanation:

Whole Number : It is defined as non-negative integer whose fraction or decimal part is always 0.

Now, it is given that q is a whole number between 42.3 and 43.1

So, to find q :

The given options are :

A. q = 42.1 : As the decimal part is not 0 in 42.1 so it cannot be whole number. So this option is rejected.

C. q = 43.4 : As the decimal part is not 0 in 43.4 so it cannot be whole number. So this option is rejected.

B. q = 43.0 : The decimal part in 43.0 is 0 so it is an whole number.

Also 42.3 < q = 43.0 < 43.1

So, the required value of q = 43.0

Hence, The option B. q = 43.0 is correct

Mariulka [41]2 years ago

7 0

42.3 < 43 < 43.1
43 is inbetween the two values, so it can be q.

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Vera_Pavlovna [14]

The margin of error is ±2%

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1 year ago

How many lots of 10 second are there in 10 minutes

Vlad [161]

Answer:

Step-by-step explanation:

We can easily solve this by finding out how many 60 seconds are in 10 minutes, and then dividing by 10.

To do that, multiply 60 seconds by 10, since there are 60 seconds in each minute.

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2 years ago

Estimate the product. Then find the actual product.

Artist 52 [7]

Answer:

it is in the steps 4443.6 actual product

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1 year ago

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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 20 feet,

Harman [31]

First, let's list the lengths of the sides in descending order.

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From the listings above, we see that he sides measuring 14 and 6 are corresponding.

We are looking for c which corresponds to 18.

14 is to 6 is as 18 is to c

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3 years ago

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The combined area of two squares is 17 square meters. the size of the larger Square are four times as long as the size of the sm

7nadin3 [17]

we are given that ,

The combined area of two squares is 17 square meters.

Area of square= $(side)^2$

Let the side length of smaller square be x

The size of the larger Square are four times as long as the size of the smaller square

$Area \ of \ smaller \ square \ =x^2$

So Area of larger square= $4x^2$

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Hence the smaller square has the side length= $\sqrt{\frac{17}{5}}$

So the larger square has side length= $2\sqrt{\frac{17}{5}}$

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3 years ago