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ehidna [41]
2 years ago
5

Please help this is due and i only got the second part done

Mathematics
1 answer:
Ainat [17]2 years ago
8 0

Answer:2n+13=75 n=31

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adelina 88 [10]
Galaxy B has more stars. When expanded, Galaxy A has 50,000,000 stars, while Galaxy B has 20,000,000,000 stars. Galaxy A has 2.5*10⁻³ times as many stars as Galaxy B. Galaxy B has 4*10² times as many stars as Galaxy A.
6 0
3 years ago
2.4 written in simplest form
guajiro [1.7K]
You can either write 2.4 as 12/5 ( an improper fraction) or as 2(2/5) (a mixed number).
7 0
3 years ago
The principal wants to buy 8 pencils for every student at her school. If there are 859 students, how
nordsb [41]

Answer: 6872

Step-by-step explanation:

8 x 859 = 6872

6 0
3 years ago
Read 2 more answers
Trigonometry help!! - double angle formulae
ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) -  4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) =  cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

= (cos^2(A) - sin^2(A))*cos(A) - sin^2(A)*cos(A) - sin^2(A)*cos(A)

= cos^3(A) - 3*sin^2(A)*cos(A)

=  cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

= cos(A)*(-3*cos^2(A) - 3*sin^2(A)) + 4*cos^3(A)

= cos(A)*(-3)*(cos^2(A) + sin^2(A)) + 4*cos^3(A)

= -3*cos(A) + 4*cos^3(A)

8 0
3 years ago
Find the gradient of the line joining (-1,9) and (3,5)
givi [52]

\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

   <em>Find the gradient of the line joining (-1,9) and (3,5)</em>

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

Use the slope formula:-

\boxed{\frac{y_2-y_1}{x_2-x_1}}

Replace the letters with the numbers:-

\boxed{\frac{5-9}{3-(-1)}}

\circ On simplification,

\boxed{\frac{-4}{3+1}}

\circ On further simplification,

\boxed{\frac{-4}{4}}

\circ\sf{SLOPE=-1}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

5 0
2 years ago
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