First we have to find the diagonal of the card. We do this by using the Pythagoras theorem: A^2 = b^2 + c^2
= 6^2 + 4^2
=36 + 16
= 52
A^2= 52
Sqrt A^2 = sqrt 52
A = 7.2
Since the envelopes diagonal is 7.2 inches and the card’s diagonal is 8 inches and 7.2<8. Your answer is c)
2m+5=5(m-7)-3m
first, use distributive property...
2m+5=5m-35-3m
next, combine like terms on the right side...
2m+5=2m-35
next, subtract 2m from both sides.
2m+5=2m-35
-2m -2m
you will get....
5=-35 in which is not true. This means the equation has no solution.
Answer: 
Step-by-step explanation:
We know the center of the original circle is (-6, -3). After reflecting this over the line x=2, the new center is now (10, -3).
Thus, the equation of the circle is
.
Answer:
(-(7-9))(z)-6z= 8(-6+2)
Simplify
-(-2)(z) -6z =8(-6+2)
Multiply 8*-6 and 8*2
2z -6z= -48+16
Combine like terms
2z+-6z =-32
-4z=-32
Divide both sides by -4
z=8
Step-by-step explanation: