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3 years ago

Which of the following is a correct unit of weight: kilogram, newton, grams, slugs

Mathematics

2 answers:

SpyIntel [72]3 years ago

7 0

The correct unit of weight is grams!

AveGali [126]3 years ago

5 0

Answer:

gram

Step-by-step explanation:

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There are two functions that can be used to describe the percent of people 25 years and older who have completed at least high s

Korvikt [17]

Answer:

$g(15)=93.8\%$

see the explanation

Step-by-step explanation:

Let

x ----> the number of years since 2008,

g(x) ----> the percent of people 25 years and older who have completed at least high school

we know that

$g(x)=0.008x^2+0.42x+87.5$

For x=15 years since 2008

substitute

$g(15)=0.008(15)^2+0.42(15)+87.5=93.8\%$

That means

In the year 2023 (2008+15) the percent of people 25 and older completing at least high school will be 93.8%

5 0

3 years ago

For what value of k will these pairs of simultaneous equations have no solution?

yKpoI14uk [10]

Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x= $\frac{k+3}{k-12}$
Also y= $\frac{5k}{k-12}$
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.

4 0

2 years ago

Mrs. Moore used the spinner below for a game played during Bear Time.

Tcecarenko [31]

Answer:

1/8

Step-by-step explanation:

yay

6 0

2 years ago

A bakery uses 300 pounds of flour to make 120 wedding cakes of the same size. At this rate how many pounds of flour are needed t

ElenaW [278]

The answer is 13 minutes and b

4 0

3 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago