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3 years ago

What is the equation of the line? 1 x - 4 y = 2x - 4 3x + 2 y = 2x + 2

Mathematics

1 answer:

Zarrin [17]3 years ago

7 0

Answer:

Step-by-step explanation:

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......!.!.?.!!,.??.?

e-lub [12.9K]

Do you have step one? maybe i can try it but im not that good in math

4 0

3 years ago

Please help

DedPeter [7]

Answer:

Step-by-step explanation:

Given the expression $\sqrt{10} * \sqrt{10}$ . To find the product of this two values, the following steps must be followed.

According to one of the law of indices, $\sqrt{a} = a^{\frac{1}{2} }$

$\sqrt{10} * \sqrt{10}\\= 10^{\frac{1}{2} }* 10^{\frac{1}{2} }\\= 10^{\frac{1}{2}+\frac{1}{2}}\\ = 10^{1} \\= 10$

The product is 10

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3 years ago

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Two people at the opposite ends of a bridge see a boat under the bridge

KATRIN_1 [288]

Do they get on it? I don;t understand your question.

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3 years ago

What is the decimal multiplier for 5%?

timama [110]

Answer:

0,05

Step-by-step explanation:

$5\% \\ \\ = \frac{5}{100} = 5 \div 100 \\ \\ ={ \boxed{ \bold{ 0,05}}}$

4 0

3 years ago

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What is the derivative of <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7BIn%28x%29%7D%7Bx%7D~%3F" id="TexFormula1" title

Stella [2.4K]

Answer and Step-by-step explanation:

$Greetings!$

$Let's~answer~your~question!$

→ $By~quotient~rule,$

$y'=\frac{\frac{1}{x}*x~-~In~x*1 }{x^2} =\frac{1-In~x}{x^2}$

→ $This~ problem ~can ~also ~be ~solved ~by~ the ~Product~ Rule:$

$y'=f'(x)~g(x)+f(x)~g(x)$

→ $The~ original~ function ~can~ also~be~ rewritten~ using ~negative~ exponents:$

$f(x)=\frac{In(x)}{x}=In(x)*x^-^1$

$f'(x)=\frac{1}{x} *x^-^1+ln(x)*-1x^-^2$

$f'(x)=\frac{1}{x}*\frac{1}{x}+In(x)*-\frac{1}{x^2}$

$f'(x)=\frac{1}{x^2}-\frac{In(x)}{x^2}$

$f'(x)=\frac{1-In(x)}{x^2}$

3 0

3 years ago