Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
Thus, the required equation of the line is y=x-8.
Answer:
About 7% is the anwser i tried 4% and i got it wrong and it said 7 was correct
Step-by-step explanation:
<h3>
Need to FinD :</h3>
- We have to find the measures of other two angles of triangle.
We know that,
- The other two angles of triangle are in the ratio of 3 : 14. So, let us consider the other two angles of the triangle be 3x and 14x.
Angle sum property,
- The angle sum property of triangle states that the sum of interior angles of triangle is 180°. By using this property, we'll find the other two angles of the triangle.
∴ Hence, the value of x is 10°. Now, let us find out the other two angles of the triangle.
Second AnglE :
∴ Hence, the measure of the second angle of triangle is 30°. Now, let us find out the third angle of triangle.
Third AnglE :
∴ Hence, the measure of the third angle of the triangle is 140°.
F(x) is a quadratic. The y intercept, therefore, is equal to the c value.
The y intercept here is -4.
For g(x), you can tell that the y intercept is 0 because that's the value of y when the x value is 0.
For h(x), the chart specifies that when x=0, y=-2, so the y intercept is -2.
Of these three values, 0 is the largest.
Final answer: g(x)
