I need help with number 10

Mathematics

1 answer:

lukranit [14]2 years ago

6 0

A)
Knights:
25n-C+1250=0
25n+1250=C
C=25n+1250

Legions:
30n+995-C=0
30n+995=C
C=30n+995

b)
fixed cost=b in y-intercept form
variable cost, dependent on n=m in y-intercept form
Knights:
fixed=1250
variable=25

Legions:
fixed=995
variable=30

c)
insert 45 into n for both formulas:

Knights:
25*45+1250=1125+1250=2375

Legions:
30*45+995=1350+995=2345

d)With 45 guests the Legion's Banquett Hall is cheaper, but due to the higher variable cost this changes with a few more people.
calculate break even point:
difference in variable cost=5 -> per person the cost difference will decrease by this much if another person joins
current price difference: 2375-2345=30
30/5=6 -> if there are 6 additional guest (total= 51) they will cost the same
if there are more than 6 additional guest (total >51) the knight's banquett will be cheaper.

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this is the rust of the questions please please some one helps me because I really try my best to solve it . thank you

lyudmila [28]

Answer:

x = 24.

r $\ne$ 0.

Step-by-step explanation:

2. The given equation is:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.

b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.

c) We have the equation:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

Multiplying throughout by 6, we get:

$\frac{6}{2}(x - 4) = \frac{6}{3} x + 6(2)$

$\implies 3(x - 4) = 2x + 12$

$\implies 3x - 12 = 2x + 12$

$\implies x = 24$

Therefore, the solution of the equation is 24.

3. The given equation is: $ry + s = tx - m$

To solve for y:

We can rearrange the equation as:

$ry = tx - m - s$

$\implies y = \frac{tx - m - s}{r}$

or, $y = \frac{tx - (m + s)}{r}$

Note that we have to impose a condition on variable $r$ . It would be that $r$ can never be zero. i.e., $r \ne 0$ . Otherwise, the value of $y$ would be undefined.