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LiRa [457]
2 years ago
12

I need help with number 10

Mathematics
1 answer:
lukranit [14]2 years ago
6 0
A)
Knights:
25n-C+1250=0
25n+1250=C
C=25n+1250

Legions:
30n+995-C=0
30n+995=C
C=30n+995

b)
fixed cost=b in y-intercept form
variable cost, dependent on n=m in y-intercept form
Knights:
fixed=1250
variable=25

Legions:
fixed=995
variable=30

c)
insert 45 into n for both formulas:

Knights:
25*45+1250=1125+1250=2375

Legions:
30*45+995=1350+995=2345

d)With 45 guests the Legion's Banquett Hall is cheaper, but due to the higher variable cost this changes with a few more people.
calculate break even point:
difference in variable cost=5 -> per person the cost difference will decrease by this much if another person joins
current price difference: 2375-2345=30
30/5=6 -> if there are 6 additional guest (total= 51) they will cost the same
if there are more than 6 additional guest (total >51) the knight's banquett will be cheaper.


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3 years ago
How do I know if an equation has one solution no solution or infinitely many solutions?
Lemur [1.5K]

Answer:  If the equation ends with a false statement (ex: 0=3) then you know that there's no solution. If the equation ends with a true statement (ex: 2=2) then you know that there's infinitely many solutions or all real numbers.

Step-by-step explanation:

3 0
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What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64
marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are 2x+y\geq 8 -------(1)

x+y \geq 6   ------------- (2)

x \geq 0, y \geq 0  -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, 2\times 0+0\geq 8⇒0\geq 8 ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, 0+0\geq 6⇒0\geq 6 ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4),  C= 46

At B≡(6,0),  C= 42

Thus at B, C is minimum, And its minimum value = 42


5 0
3 years ago
Read 2 more answers
D=5.32 to the nearest hundredth
babymother [125]
<span>5.32 to the nearest hundredth
= 5.32

hope that helps</span>
3 0
3 years ago
Write a quadratic function whose zeros are -12 and -2.
AnnZ [28]

Answer:

(x+12) (x+2)

x(x+12)+2(x+12)

x^2+12x+2x+24

x^2+14x+24

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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