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3 years ago

Need an answer asap!!

Mathematics

2 answers:

Goryan [66]3 years ago

8 0

the last option because the answer is

−6<x<0 or x>2

Oksanka [162]3 years ago

4 0

Simply ask for help.

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Please help, been struggling with this for almost a week now.

nikitadnepr [17]

Answer:

$A \approx 1140.3\ units^2$

Step-by-step explanation:

To solve this problem we first need to find the diameter of the circle. We are told the point $N$ is the circle, so we can assume it is the center of the circle. To find the diameter we can use the Pythagorean Theorem:

$a^2 + b^2 = c^2\\40^2 + 9^2 = c^2\\1600 + 81 = c^2\\1681 = c^2\\\sqrt{1681} = c\\41 = c$

The diameter is $41$ units, which means the radius is $\frac{41}{2}$ . From here we can calculate the area of the circle:

$A_c = \pi r^2\\A_c = \pi (\frac{41}{2})^2\\A_c = \pi 420.25\\A_c \approx 1320.25$

Now we need to subtract the area of the triangle from the area of the circle. Calculate the area of the triangle:

$A_t = \frac{bh}{2}\\A_t = \frac{40 \times 9}{2}\\A_t = \frac{360}{2}\\A_t = 180$

Subtract the triangle area from the circle area to get the area of the shaded area:

$A = A_c - A_t\\A = \pi420.25 - 180\\A = 1140.25431\\A \approx 1140.3\ units^2$

5 0

2 years ago

50 pounds to 35 pounds percentage of change

iVinArrow [24]

Answer:

30%

Step-by-step explanation:

<h2><u>Percentage change </u></h2><h3>formula :</h3>

$\frac{change}{origional} * 100$

= 50 - 35 = 15

= $\frac{15}{50}*100\\$

4 0

4 years ago

Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p

scZoUnD [109]

Answer:

The probability that they will teach different courses is $\frac{2}{3}$ .

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Compute the probability that they will teach different courses as follows:

$P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}$

Thus, the probability that they will teach different courses is $\frac{2}{3}$ .

3 0

3 years ago

Use this equation of the circle: (x-2)2+(y+6)2=4

ki77a [65]

Answer:

Center: (2,-6)

Radius =2

Diameter = 4

Área = 12.57

Circumference = 12.57

Step-by-step explanation:

6 0

3 years ago

Estimates by first rounding each number to the place value 1.8×3.62

Y_Kistochka [10]

By estimation you have:

3.62 ≈ 4.0

1.8 ≈ 2.0

2.0 x 4.0 = 8.0

5 0

1 year ago