Find the value of the variable if P is between J & K. JP = 3y+1 ; PK = 12y - 4 ; JK = 75

1 answer:

3 0

<span>JP + PK = JK
3y + 1 + 12y - 4 = 75
15y -3 = 75
15y = 75 +3
15y = 78
y = 78/15
y = 5.2

answer is </span><span>a. 5.2</span>

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Information for the park trails is displayed at the entrance to the park office.

Lisa [10]

So you can use tan here, which is opposite/adjacent. (We're looking for the Adjacent)

Since we know Trail E is 1700, we're looking for the patch of trail A that is the adjacent. So if we put 42 into a tan calculator we get about 0.9.

So that means that 1,700 / adjacent = 0.9.

So we can also say

1,700/0.9 = adjacent

or, 1,700/0.9 = 1888.89

Now, we have the little patch of trail A in the smaller right triangle. We want to find the patch of trail A in the larger right triangle.

So just do 5,000 - 1,888.89

You get 3111.11

So if we know that's that, and we're looking for the hypotenuse, or Trail B, we can use cosine, because that's adjacent / hypotenuse.

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So 3111.11 / hypotenuse = 0.74

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3 years ago

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the

san4es73 [151]

Answer:

We get value of the value of b = 5

Step-by-step explanation:

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, then m=m equals negative StartFraction 1 Over 6 EndFraction.. What is the value of b?

We have slope m: $m=-\frac{1}{6}$