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solniwko [45]
3 years ago
13

URGENT :find x and y please thank youuuu

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0
180-135=45 Degrees
y=45
135/3=45
x=45
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The number 15, 56 rounded to the nearest thousand is 15,000. Which numbers could be the missing digit?
Virty [35]

The numbers 0, 1, 2, 3, 4 could all be the missing digit because they're all numbers that round down. hope this helped!

4 0
4 years ago
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The cost of taking your pet aboard the air flight with you in the continental US varies according to the airlines. The five numb
sergeinik [125]

Answer:

Lowest is 100

Highest is 125

Step-by-step explanation:

We use the 5 number summary to be the foundation of a graphical representation referred to as the box plot. One box would move from one quartile which is the lowest quartile Q1 to the another quartile Q3 which is the upper quartile.

Now if a box plot is to be made given the the information in this question, the box is going to go from Quartile 1 to Quartile 3.

Then the Lowest value would be 100 and the highest 125

3 0
3 years ago
What’s the answer??(SOMEONE PLEASE HELP ME)
Evgesh-ka [11]

To find f^{-1}, you can switch the "x" and "f(x) or y" in the equation.

f(x) = \sqrt[3]{x-2} +8

y = \sqrt[3]{x-2}+ 8

x = \sqrt[3]{y-2}+8

Now you need to isolate the "y"

x = \sqrt[3]{y-2}+8   Subtract 8 on both sides

x - 8 = \sqrt[3]{y-2}  Cube ( ³ ) each side to get rid of the ∛

(x-8)^{3} = (\sqrt[3]{y-2}) ^{3}

(x-8)^{3} = y -2   Add 2 on both sides

(x-8)^{3}+2 = y


f^{-1} = (x-8)^{3} + 2


5 0
3 years ago
Read 2 more answers
Can anyone help with this question? Ty
gizmo_the_mogwai [7]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
(1 point) Find the length L and width W (with W≤L) of the rectangle with perimeter 100 that has maximum area, and then find the
Vilka [71]

Answer:

Width = 25

Length = 25

Area = 625

Step-by-step explanation:

The perimeter of a rectangle is given by the sum of its four sides (2L+2W) while the area is given by the product of the its length by its width (LW). It is possible to write the area as a function of width as follows:

100 = 2L+2W\\L = 50-W\\A=LW=W*(50-W)\\A=50W - W^2

The value of W for which the derivate of the area function is zero is the width that yields the maximum area:

A=50W - W^2\\\frac{dA}{dW}=0=50 - 2W\\ W=25

With the value of the width, the length (L) and the area (A) can be also be found:

L=50-25 = 25\\A=W*L=25*25\\A=625

Since the values satisfy the condition W≤L, the answer is:

Width = 25

Length = 25

Area = 625

8 0
3 years ago
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