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sergiy2304 [10]

3 years ago

8

The graph of a proportional relationship is given along with an equation for a difference relationship. Which situation has a gr

eater unit rate?
•A
• B
•C

2 answers:

Contact [7]3 years ago

6 0

Answer:

its b

Step-by-step explanation:

yo welcome....

NANNIIII?!

irakobra [83]3 years ago

4 0

Answer:

I think its C

Step-by-step explanation:

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Today Jan wants to run less than 7 12th Write a fraction with a denominator of 4 to represent a distance that is leso than 7 12t

Lelechka [254]

2 to the 3rd power of 4

7 0

3 years ago

Read 2 more answers

Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$

bagirrra123 [75]

Answer:

$5\sqrt{3}$

Step-by-step explanation:

$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}$

All Done!

8 0

3 years ago

Read 2 more answers

Are these answers correct?

Nikolay [14]

Answer:

You're correct.

Step-by-step explanation:

3 0

3 years ago

Here all me points i have 0 now

marin [14]

Answer:

thanks

Step-by-step explanation:

4 0

3 years ago

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

3 years ago