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Iteru [2.4K]
3 years ago
9

why can you write a subtraction problem as an addition problem? How do you write a subtraction problem as an addition problem?

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0
To write a subtraction problem as an addition problem, just switch the numbers a little. For example:

11 - 5 = ?

Just write it like this:

5 + ? = 11

These two problems will get the same answer. Watch:

11 - 5 = 6

5 + 6 = 11

Both of these work because all three numbers ( two main ones and the answer) Can be switched around in different orders depending on the operation.

Hope this helps, WyattMarine501
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A scatter plot showed a positive correlation for 11 bowlers. As the number of strikes, s, a bowler made in a game increased, the
almond37 [142]

Answer:

s = 4

Step-by-step explanation:

The equation for the line of best fit for the data is p=25s+40.

Where p is no. of points and s is no. fo strikes

We need to find the number of strikes made by a bowler with 140 points.

Put p = 140

p=25s+40

140 = 25s+40

Subtract 40 to both sides,

140-40 = 25s+40-40

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⇒ s = 4

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What is the median of this data set<br> 71,37,22,81,65,54,52,41,48,71
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Answer:

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3 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?
yaroslaw [1]

Answer:

The value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

4x^2-3x+9=2x+1

which could also be written as:

4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0

The quadratic formula for the quadratic equation of the type:

ax^2+bx+c=0 is given as:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}

Hence, the value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

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