The probability of getting a Club given that the card is a Ten is 0.25.
According to the statement
we have given that the there is a deck of the 52 cards and we have to find the conditional probability that the card is a club and the given card is a 10 number card.
So, For this purpose we know that the
Conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.
And according to this,
The probability P is
P(Club) = 13/52 = 1/4
P(Ten) = 4/52 = 1/13
P(Club and Ten) = (1/4)(1/13) = 1/52
And we know that the
P(Club|Ten) = P(Club and Ten)/P(Ten)
And then substitute the values and it become
= (1/52)/(1/13) = (1/52)(13/1)
= 13/52 = 1/4
= 0.25
So, The probability of getting a Club given that the card is a Ten is 0.25.
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The total outcomes of creating a password is 20
<h3>How to determine the total outcomes creating different passwords with the given characters and numbers?</h3>
The given parameters are
Letters = 3
Digits = 5 digits i.e 0, 2, 4, 6, or 8.
From the question, the digits and the letters cannot be repeated.
So, we have:
Possible letters = 3 characters (position fixed)
Digits = 2 numbers
So, the total outcomes of creating different passwords is
Total = 1 * 1 * 1 * 5 * 4
Evaluate the product
Total = 20
Hence, the total outcomes of creating a password is 20
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Step-by-step explanation:
time ∝ number of door 1
time . ∝ 1/number of people. 2
compare equation 1 and 2
time . ∝ number of door / number of people
put k as constant
time = k number of door / number of people. 3
time =2. people=4 door = 10
putting in equation 3
2 = k (10)/(4)
2×4/10 = k
8/10 =k
4/5 =k
putting in equation 3
time= 4/5 number of door / number of people
now time =5 door= 25 people=?
5=4/5 (5)/ (number of people)
number of people =4/5 ×25/5
number of people= 4
Answer:
2^3×6-5÷3-3×4^-4 solving 8×1÷0×0=8÷0= 8
There’s this website you can search on your phone/laptop called Desmos
