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Free_Kalibri [48]
4 years ago
8

Help!!!!!!

Mathematics
2 answers:
Talja [164]4 years ago
8 0
I set up these three factors
(x-2) * (x-3) * (x-5) and then multiplied these to get this equation:

x^3 -10x^2 +31x -30 = 0

olga nikolaevna [1]4 years ago
3 0

Answer:

The cubic polynomial function whose graph has zeroes at2,3,5  is given by

x^3-10x^2+31x-30.

No, any of the roots ave no multiplicity.

The function P(x)= x^3-10x^2+31x-30

Step-by-step explanation:

Given  graph has zeroes at 2, 3and 5

 x=2

x-2=0

x=3

x-3=0

x=5

x-5=0

Multiply (x-2) , (x-3) and (x-5)

We get

(x-2)\times (x-3)\times (x-5)

after multiply we get an equation of cubic polynomial

<h3>= x^3-10x^2+31x-30 </h3><h3>Multiplicity : If a value of root repeated then the repeated value of root is called multiplicity.</h3>

Therefore , any root have no multiplicity because value of any root not repeated.

The function that has these roots is  given by

<h3> p(x)=x^3-10x^2+31x-30.</h3>

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Alla [95]

Answer:

Step-by-step explanation:

4x+27

----  ----

4       4

x=6.75 or x=7

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3 years ago
What is the midpoint between (-6,2) and (10,4)
mario62 [17]

Answer:

(2,3)

Step-by-step explanation:

To find the x-coordinate of the midpoint, find the average of -6 and 10.  It is 4/2, or 2.  

To find the y-coordinate, proceed similarly.  Find the average of 2 and 4.  It is 3.

Thus, the midpoint is (2, 3).

7 0
3 years ago
The Silvertons are looking at purchasing a new car for their family. Steve Silverton wants to purchase a 2019 Chevrolet Tahoe wh
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hree vertices of a rectangle are given. Find the coordinates of the fourth vertex. (–2, 4), (4, 0), (2, –3)
zhannawk [14.2K]
V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?

V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4

V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4

dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1

V4=(x4, y4)→V4=(-4, 1)

Answer: The coordinates of the fourth vertex are (-4,1)

5 0
3 years ago
Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
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