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valkas [14]
2 years ago
14

Find the area 7cm. 20cm. 11cm. 14cm. ( will mark brainlest)​

Mathematics
1 answer:
nignag [31]2 years ago
6 0

Answer:

217

Step-by-step explanation:

we split the shape into 2 different rectangles and find the sum of their area.

small rectangle: 7 × 11 = 77

large rectangle 7 × 20 = 140

140 + 77 = 217

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How many two-step paths are there from C to B? (Use a matrix to determine this.)
Marta_Voda [28]

Answer:

The answer is C. Since B is one half step up from B flat, and C

is one half step up from B, and two halves make a whole :)

5 0
3 years ago
Maria put trim around a banner that is the shape of a triangle. Each side is 21 inches long. Maria has 3 4 foot of trim left. Wh
Sergio039 [100]

We have been given that Maria put trim around a banner that is the shape of a triangle. Each side is 21 inches long.

The amount of trim will be equal to perimeter of triangle. The perimeter of given triangle will be 3 times each side length that is 3\times 21=63 inches.

Now we need to convert 63 inches into feet.  

12 inches = 1 feet

63 inches = \frac{63}{12}  feet = 5.25 feet.

We are also told that Maria has \frac{3}{4} foot of trim left, so total length of trim would be trim used plus trim left that is 5.25+\frac{3}{4}=5.25+0.75=6 feet.

Since we need to find length of trim in yards, so we will convert 6 feet into yards.

3 feet = 1 yard

6 feet = \frac{6}{3} yards = 2 yards

Therefore, the length of the trim was 2 yards.

5 0
4 years ago
Solve the system of equations. What is the solution?<br> 10x – 4y = 12<br> 5x + 2y = 14
Stells [14]

Answer is 2

Step-by-step explanation:

7 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
What is 10 tens minus 1 ten 1 tenth
Natasha2012 [34]
10*10-(1*10+1*\frac{1}{10})\\100-(10+\frac{1}{10})\\100-(\frac{100}{10}-\frac{1}{10})\\\frac{1000}{10}-(\frac{99}{10})\\\frac{901}{10}\\90.1

90.1
4 0
3 years ago
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