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grigory [225]
3 years ago
7

Consider the two data sets. Which has the higher mean and median? What is the higher mean and median?

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Set 1 mean - 23.625

Set 2 mean - 23.5

Set 1 median - 23.5

Set 2 median - 22.5

This shows the answer is D :)

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Can someone please teach me how to add, subtract, multiply and divide negative numbers?
dedylja [7]
If both numbers are negative u add those up and ur answer will be a negative. so number one is negative 9.
if there is more positive ur answer will be a positive. so number 2 is 13.
number is more complicated so negative 3 +4 is 1 because u have more positive and u just subtract those then 1 minus 8 equals negative 7 and negative 7 minus 7 is 0. hope this helps
3 0
2 years ago
Read 2 more answers
2.
Virty [35]

Answer:

1/9 is probably most likely the correct answer

3 0
2 years ago
Re-write the equation without the h component.
levacccp [35]

Answer:

f(x) = 2[\frac{3^x}{9}] + 2

f(x) = 8(4)^x

Step-by-step explanation:

Given

f(x) = 2(3)^{x-2} + 2

f(x) = \frac{1}{2}(4)^{x+2}

Required

Remove the h component

In a function, the h component is highlighted as:

f(x) = a^{x+h}

So, we have:

f(x) = 2(3)^{x-2} + 2

Split the exponents using the following law of indices:

a^m/a^n = a^{m-n}

f(x) = 2*\frac{3^x}{3^2} + 2

f(x) = 2*\frac{3^x}{9} + 2

f(x) = 2[\frac{3^x}{9}] + 2

<em>The h component has been removed</em>

f(x) = \frac{1}{2}(4)^{x+2}

Split the exponent using the following law of indices

a^{m+n} =a^m * a^n

So, we have:

f(x) = \frac{1}{2}(4)^x * 4^2

Express 4^2 as 16

f(x) = \frac{1}{2}(4)^x * 16

Divide 16 by 2

f(x) = 8(4)^x

3 0
2 years ago
5. Classify each triangle by its angle and sides
PIT_PIT [208]

Answer:

5 is D

6 is C

Step-by-step explanation:

Define:

Equilateral - All sides and angles are congruent

Isosceles: Two congruent sides and two congruent angles

Scalene: No congruent sides or angles

Right triangle: A triangle with a right angle ( note that a right angle has a measure of 90 degrees )

obtuse triangle: A triangle with an obtuse angle ( obtuse angles have a measure of more than 90 degrees. )

Acute triangle : A triangle with an acute angle ( an acute angle has a measure of less than 90 degrees )

Answer:

the triangle shown in # 5 has a right angle and 2 congruent sides and angles

Therefore the triangle in #5 is a right isosceles

The triangle shown in #6 has an angle with a measure that is more than 90 degrees and have no congruent sides or angles therefore the triangle in #6 is an obtuse scalene.

3 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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