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grigory [225]
3 years ago
7

Consider the two data sets. Which has the higher mean and median? What is the higher mean and median?

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Set 1 mean - 23.625

Set 2 mean - 23.5

Set 1 median - 23.5

Set 2 median - 22.5

This shows the answer is D :)

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use the explicit formula an = a1 + (n - 1) * d to find the 500th term of the sequence below. 24,30,36,42,48,... A. 3018 B. 3042
marishachu [46]

Answer:

Option A.

Step-by-step explanation:

The given sequence is  

24, 30, 36, 42, 48, ...

It is an AP. Here,  

First term = 24

Common difference = 30-24 = 6

The given explicit formula for nth term is

a_n=a_1+(n-1)d

where, a_1 is first term, d is common difference.

Substitute a_1=24, d=6 \text{ and }n=500 in the above formula.

a_{500}=24+(500-1)(6)

a_{500}=24+(499)(6)

a_{500}=24+2994

a_{500}=3018

The 500th term of the sequence is 3018.

Therefore, the correct option is A.

3 0
3 years ago
The numeral 16 is a _____ of 4 because it is the product of a given number sbd any whole number
S_A_V [24]

Answer:

perfect square

Step-by-step explanation:

A perfect square is a number multiplied by itself:

16 = 4^2 = 4 * 4

5 0
2 years ago
Which of the following is equal to the fraction below?
Alecsey [184]
Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?
4 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
1 year ago
Write the slope-intercept form of the equation of the line that passes through the given points.
zmey [24]

Answer:

Slope=1

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where x1,y1= (1, 1) and X2,y2=(-3, -3)

Slop=1+3/1+4

=4/4

=1

So the slope is 1.

8 0
3 years ago
Read 2 more answers
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