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Iteru [2.4K]
3 years ago
8

Simplify the expression (-3x)^4

Mathematics
1 answer:
Sati [7]3 years ago
8 0
(-3x)⁴

Basically, just do this :

(-3x) × (-3x) × (-3x) × (-3x)

So now you have 9x² × 9x²

9 × 9 = 81

x² × x² = x⁴

So, your answer is 81x⁴

~Hope I helped!~
You might be interested in
what is the equation of the line that passes through the point (-2,-2) and is parallel to the line 3x-y=2
VashaNatasha [74]

Answer:

y = 3x + 4

Step-by-step explanation:

Turn the equation from standard form to slope intercept form. So, solve for y.

3x - y = 2

~Subtract 3x to both sides

-y = 2 - 3x

~Divide -1 to everything

y = -2 + 3x

~Reorder

y = 3x - 2

The slope of a parallel line is the same as the original.

Find the new y-intercept.

y = 3x - 2

-2 = 3(-2) + b

-2 = -6 + b

4 = b

y = 3x + 4

Best of Luck!

7 0
3 years ago
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
How do I do this, it is for geometry (ignore the answer it was a guess) thank you so much.
Evgesh-ka [11]

Answer:

AC is about 41. 095 miles long.

Step-by-step explanation:

You can use the Law of Cosines to solve this: c^2 = a^2 + b^2 – 2ab cos(C)

Substitute in your values, and you're good to go!

c^2=16^2+28^2-2(16)(28)(cos(117))

c^2 = 256 + 784 - 896(cos(117))

c = sqrt(1040 - 896(cos(117)))

c is about 41. 095 miles long.

4 0
3 years ago
Read 2 more answers
What is the answer to 32 to the power of 3x+5 = 8 to the power of x-1
KIM [24]

Answer:

-2.333333333333........

5 0
3 years ago
Select the correct answer.
kap26 [50]

Answer:

The answer to your question is the letter C

Step-by-step explanation:

To answer this question just look at the graph, the solution to the system of the quadratic equation and the linear function, are the points where these function cross.

The first point where these functions cross is Point C

The second point where these functions cross is Point E

5 0
3 years ago
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