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Kazeer [188]
3 years ago
8

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

is divided by 7?
Mathematics
1 answer:
Blizzard [7]3 years ago
6 0
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
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The lowest value of the range of the function shown in the graph is -2.

<h3>What is range of a function?</h3>

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1 year ago
FOR 90 POINTS PLEASE HELP
miskamm [114]

Answer:

Question 1: RS=47

Question 2: x=6

Step-by-step explanation:

Question 1:

Step 1: 3x+5=2x+15+6x-37

Step 2: 3x+5=8x-22/2

Step 3: 3x+5=4x-11

Step 4: x=16

Step 5: 2(16)+15=32+15=47

<u>RS= 47</u>

<u />

Question 2:

Step 1: 7x+2+25x-14=180

Step 2: 32x-12=180

Step 3: 32x=192  (divide 32 from each side)

<u>x=6</u>

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