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QveST [7]
3 years ago
8

I need helphdhhd;hhdhdjdjieieieiieieii

Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0
The answer is:  " 2x¹⁶ y " .
________________________________________
This is the "most simplified" version of the expression given.
________________________________________

Explanation:
________________________________________

Given:  "2xy (x⁵)³ " ;  Simplify .
_____________________________________

Note:  (x ⁵) ³ = x⁽ ⁵ * ³ ⁾  =  x ⁽¹⁵⁾ ;
______________________________________
Rewrite:  

2xy (x⁵)³ = 2xy x⁽¹⁵⁾ ; 

Rewrite:

2 * x * x⁽¹⁵⁾ * y ;

Note:   "x * x⁽¹⁵⁾ = x¹  *  x¹⁵  = x⁽¹ ⁺ ¹⁵⁾ = x¹⁶ ;

Rewrite:  " 2x¹⁶ y " .
__________________________________________
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One of the same side angles of two parallel lines is 20° smaller than the other one. Find all angles.
Elden [556K]

Answer: 80 and 100


Step-by-step explanation:

180/2=90

90+10=100

90-10=80

8 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (3, 0) and (6, -1)
Shalnov [3]
Y= -1/3x + 1

Please mark BRAINLEST!!

3 0
3 years ago
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Kim creates a model of a building. The scale of her model building is 1 foot to inch. Some of the measurements are
malfutka [58]

Answer:

height: 16 inch

length of base: 10 inch

width of base: 50 feet

Step-by-step explanation:

128*(1/8)=16 inch

80*(1/8)=10 inch

x*1/8=6.25

x=6.25*8=50 feet

7 0
3 years ago
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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

(\left {{20} \atop {2}} \right. )=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

(\left {{3} \atop {2}} \right. )=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

\frac{3}{190}\\ =0.01579\\=0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0
2 years ago
Can someone please help me, it's science and math put together I just don't understand how to do this problem maybe it's the way
sergij07 [2.7K]
What ?  What ? 
Did you write the first two answers in pencil ?
They're correct !  Just do the other two exactly the same way.

-- Do the division problem printed in the "Distance ..." column.

-- Multiply the answer by  0.1 .

-- Write the new answer in the last column.
6 0
3 years ago
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