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3 years ago

Suppose the x-intercept of f(x) is (p,0) and the x-intercept of g(x) is (q,0). What is the value of p+q?

Mathematics

1 answer:

zubka84 [21]3 years ago

7 0

Answer:

im pretty sure its -1 because thats the answer i had before my answers didnt save n the same test you had. im not 100 percent sure though

Step-by-step explanation:

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What is the answer to... 5m+8n-2(3m-n)? Show step by step

Alexxx [7]

Answer:

The answer is

Step-by-step explanation:

5m+8n-2(3m-n)

Expand the terms in the bracket

That's

5m + 8n - 6m + 2n

Group like terms

We have

8n + 2n + 5m - 6m

Simplify

The final answer is

10n - m

Hope this helps you

6 0

3 years ago

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

2 years ago

You have $90,000 in cash. You can deposit it today in a mutual fund earning 7.5

Lady bird [3.3K]

I will go to the Bahamas instead and think about later

5 0

3 years ago

Factor the polynomial

arlik [135]

Answer:

(5x+12) (5x-12)

Step-by-step explanation:

Use the difference of squares fromula. $a^{2} -b^{2} =(a+b)(a-b)$

Where a = 5x and b =12.

4 0

3 years ago

Is the median always sometimes or never one of the data values. explain

blondinia [14]

It can somteimes be one of the data values. When there's an odd set of numbers, the median will always be one of the data values. When there's a even set of numbers, the median will sometimes be one of the data values.
Even:
2, 3, 4, 5, 6, 7
Now, we need to find the number between 4 and 5, which is 4.5, 4.5 doesn't show up in the data set.
2,3, 5, 5, 6, 7
The middle of 5 and 5 is 5 since it's the same number. 5 does show up in the data set.
So, the median sometimes is one of the data values.

6 0

3 years ago

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