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2 years ago

Which equation represents a proportional relationship between the x and y values?

Mathematics

2 answers:

allochka39001 [22]2 years ago

5 0

Answer:

y = kx

Step-by-step explanation:

We have to write an equation that states that the relationship between x and y is proportional.

Since x and y are proportional, so we can write symbolically

y ∝ x

⇒ y = kx {Where k is the constant of proportionality}

So, this is the required equation. (Answer)

Geometrically it signifies that it is a straight line having constant slope k and it passes through the origin.

telo118 [61]2 years ago

3 0

Answer:

The answer is D. y = −2x

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In the matrix equation below, what are the values of x and y?

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The value of x = 5 and y = 2

The correct answer is last option

Step-by-step explanation:

From the figure we can see that, subtraction of two matrices.

The resultant matrix shows the corresponding terms difference.

<u>To find the value of x</u>

1/2(x + 3) - (3*(-1)) = 7

x/2 + 3/2 +3 = 7

x/2 +3/2 = 7 - 3 = 4

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<u>To find the value of y</u>

8/2 -3 (y +1) = -5

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3 years ago

A metallurgist needs to make 12.4 lb. of an 10) alloy containing 50% gold. He is going to melt and combine one metal that is 60%

sergeinik [125]

Now, let's say, we add "x" lbs of the 60% gold alloy, so.. how much gold is in it? well, is just 60%, so (60/100) * x, or 0.6x.

likewise, if we use "y" lbs of the 40% alloy, how much gold is in it? well, 40% of y, or (40/100) * y, or 0.4y.

now, whatever "x" and "y" are, their sum must be 12.4 lbs.

we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.

$\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{gold~\%}{quantity}&\stackrel{gold}{quantity}\\
&------&------&------\\
\textit{60\% alloy}&x&0.6&0.6x\\
\textit{40\% alloy}&y&0.4&0.4y\\
------&------&------&------\\
\textit{50\% alloy}&12.4&0.50&6.2
\end{array}$

$\bf \begin{cases}
x+y=12.4\implies \boxed{y}=12.4-x\\
0.6x+0.4y=6.2\\
-------------\\
0.6x+0.4\left( \boxed{12.4-x} \right)=6.2
\end{cases}
\\\\\\
0.6x-0.4x+4.96=6.2\implies 0.2x=1.24\implies x=\cfrac{1.24}{0.2}
\\\\\\
x=\stackrel{lbs}{6.2}$

how much of the 40% alloy? well, y = 12.4 - x.

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