We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
2.56
Step-by-step explanation:
I'm pretty sure, I'm sorry if its wrong
Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To find b, you first need to calculate slope and see where the line intersects the y-axis.
To get m (slope), use the form y1 - y2/x1 - x2. It would look like this:
2 - 12/-1 - 4. This simplifies to:
-10/-5, which further simplifies to 2. Now, graph the points to find y....
My graph shows that the line intersects at (0, 4), so slope-intercept form would look like:
y = 2x + 4 (remember, 2 is the slope and 4 is the y-intercept)
Hope this helps.
(x^2 - 1)(x^6 + x^4 + x^2) =
x^2(x^6 + x^4 + x^2) - 1(x^6 + x^4 + x^2) =
x^8 + x^6 + x^4 - x^6 - x^4 - x^2 =
x^8 - x^2 <==
The length of the ladder is 25 feet.
<u>Explanation:</u>
Height of the House, h = 24 feet
Distance between the house and the ladder, b = 7 feet
length of the ladder, x = ?
The house makes 90° with the base of the ladder.
Using pythagoras theorm,
x² = h² + b²
x² = (24)² + (7)²
x = √625
x = 25
Therefore, the length of the ladder is 25 feet.
