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Hoochie [10]
3 years ago
15

A triangle can be formed with the lengths 10 cm, 5 cm and 14 cm.​

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer: yes.

Step-by-step explanation: i dont really get this one so i just said yes

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Each block in Ton’s neighborhood is 2/3 mile long if he walk 4 1/2 blocks how far does he walk?
nataly862011 [7]

if each block is 2/3 miles long, and he walks 4 1/2 blocks, we can simply multiply to two. It looks like this:

(2/3)(4 1/2)

to multiply, make 4 1/2 into an improper fraction and multiply normally

(2/3)(9/4)

Ton walks 3 miles total.

3 0
4 years ago
Mr. Tindell divided a 6th grade class Of 80 students an into equal groups the number of students in each group was a prime numbe
zubka84 [21]

Answer:

He made 16 groups which means 5 Students in each group

Step-by-step explanation:

Because 80 divided by 16 is 5 and 5 is a prime number

3 0
3 years ago
The hypotenuse is 8 inches. The side opposite angle X is 7 inches. Angle X = ?
Alex73 [517]

Step-by-step explanation:

In the picture.

The answer is <em><u>X = 61°</u></em>

6 0
3 years ago
What is it called when transformation of the plane which reflects each point and then translates it called
Crank

The figures in a plane can be reflected, rotated, translated or dilated to produce new figures or images.

A transformation that moves all points to the same distance and in the same direction. The final figure looks the same, just moved over. It does not flip or gets rotated. It also does not change size.This type of translation is called glide reflection. Its the summation of translation and reflection.

6 0
3 years ago
Read 2 more answers
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
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