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AnnZ [28]
3 years ago
11

If 50 grams of sweats cost $2.10,find the cost of 380 of sweats,giving your answer correct to the nearest 5 cent

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

$15.95

Step-by-step explanation:

cost of 1 gram of sweet = $2.10 / 50 = 0.042

Cost of 380 g = 380 x 0.042 = $15.96

to the nearest 5 cent = 15.95

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A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57tan(27.32^0)

h\approx8.45 ft

Thus, the height of the statue is approximately, 8.45 feet.

3 0
3 years ago
You find one quarter, two dimes ,and two nickels. A. Write the dollar amount as a decimal. B.Write the dollar amount as a fracti
snow_tiger [21]
A- $1.00
B- $100/100 write 100 over 100
8 0
3 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
Describe the connections between unit rates, proportions, and rate tables.
Bas_tet [7]
They're all used for differentiating types of measurement in mathematics and science.
5 0
3 years ago
Read 2 more answers
A large spherical balloon is being deflated. When the radius of the balloon decreases from 10 ft to 5 ft, approximately how much
Xelga [282]
Volume of a sphere: V=(4/3)πr³
V1=(4/3)π10³
V2=(4/3)π5³
difference: (4/3)π10³-(4/3)π5³=(4/3)π875=3665
the answer is B.<span />
5 0
3 years ago
Read 2 more answers
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