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Paha777 [63]
3 years ago
9

J. P. Morgan Asset Management publishes information about financial investments. Over the past years, the expected return for th

e S&P was with a standard deviation of and the expected return over that same period for a Core Bonds fund was with a standard deviation of (J. P. Morgan Asset Management, Guide to the Markets, 1st Quarter, ). The publication also reported that the correlation between the S&P and Core Bonds is . You are considering portfolio investments that are composed of an S&P index fund and a Core Bonds fund. a. Using the information provided, determine the covariance between the S&P and Core Bonds. Round your answer to two decimal places. If required enter negative values as negative numbers.
Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

For this problem first we need to figure out the covariance  of the JP morgan

and its value is 24

Second we find expected return and standard deviation whose values are 9% and 34.98

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3 years ago
Find the distance round the semi circle with a diameter of<br>35 cm<br>​
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Answer: a semi circle is half a circle so 35 divided by 2 is 17.5

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3 years ago
The weight of laboratory mice follows a normal distribution, with a mean of 0.68 ounce and a standard deviation of 0.02 ounce. W
elena-14-01-66 [18.8K]

Answer:

A.99.7%

Step-by-step explanation:

We are given;

  • Mean of a distribution, μ as 0.68 ounce
  • Standard deviation, σ as 0.02 ounce
  • The range values of X between 0.62 ounce and 0.74 ounce

We are required to calculate the percentage of the weight to be between 0.62 ounce and 0.74 ounce

Step 1: Calculate the Z-score

To get the Z-score we use the formula;

Z-score = (x-μ)/σ

Therefore, when x = 0.62

Then z score = (0.62 - 0.68 ) ÷ 0.02

                     = -3

When, x = 0.74

Then, Z score = (0.74 - 0.68) ÷ 0.02

                       = 3

Step 2:  we use the Z-score table or the empirical rule

Using the Z-score table;

P(-3 < z < 3) = 99.7%.

Therefore; the percentage of mice that weigh between 0.62 ounce and 0.74 ounce is 99.7%.

7 0
3 years ago
A 5 inch × 7 inch photograph is placed inside a picture frame. Both the length and width of the frame are 2x inches larger than
Svetach [21]
The options are;
<span>a)4x+12
b)8x+24
c)2x^4+24
d)4x^2+24x+35
</span>

dimensions of the photograph 
length - 7 inch 
width - 5 inch
dimensions of the photo frame is 2x larger than both width and length 
length - 7 + 2x
width - 5 + 2x
the perimeter is sum of all 4 sides 
Perimeter = 2(7 + 2x) + 2(5 + 2x)
                 = 14 + 4x + 10 +4x
                 = 24 + 8x
correct answer is b
4 0
3 years ago
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