Answer:
10a and 5a+2a+3a
Step-by-step explanation:
6a + 4a = 10a
10a = 10a
9a is not equal to 10a
10+a is not equal to 10a
5a+2a+3a = 10a
6a - 4a is not equal to 10a
a^10 is not equal to 10a
Hope this helps! :)
D-median, because the presence of an outlier affect the data
Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:
12x11x10x9x8 different combinations.
Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.
(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.
Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)
C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792