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Jet001 [13]
3 years ago
14

The legs of a right triangle measure 6 inches and 9 inches. If is the angle between the 6-inch leg and the hypotenuse, sin = ___

__.
Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0
First find the length of the hypotenuse using pythagorean theorem
<span>c^2 = 5^2 + 7^2
c^2 = 25 + 49
c^2 = 64
c=8 (take the square root in both sides)
Since sin = opposite/hypotenuse,
sin = 5/8 = 0.625</span>
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Write an algebraic expression for each:
viktelen [127]

Answer:

X + 45

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Step-by-step explanation:

Using the keywords sum of, more than, and subtracted will help you. (You can also flip the expression since it didn't say how.

8 0
3 years ago
How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled
spayn [35]

The volume of oblique cone =\frac{1}{3} \pi r^{2} h

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = \frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)

= \frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )=4*(\frac{1}{3} \pi r^{2} h )

It means the volume becomes 4 times

3 0
3 years ago
El cuadruple de un numero mas un quinto
11Alexandr11 [23.1K]
4x+1/5
I hope this helps! I'm hoping google translated your question properly, I'm native english speaking
¡Espero que esto ayude! Espero que google tradujera tu pregunta correctamente, soy nativo de habla inglesa
4 0
2 years ago
Expand the expression −11(3c−2d)<br> using the Distributive Property.
Sladkaya [172]

Answer:

-33c+22d

Step-by-step explanation:

=(−11)(3c+−2d)

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5 0
2 years ago
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
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By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
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