Answer:
(Kind of cheating but since you're timed I'm just gonna five you the answer:
3/11
Step-by-step explanation:
I got this by guessing a bit, I used what varibles I had and 0.27 & 3 and used them.
So 3/0.27 = 11.11 (Repeating) so then I rounded this to a whole number,
3/11 = 0.27 (Repeating)
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Answer: Tis 0
Step-by-step explanation:
Answer:
Its -15 (B.)
Step-by-step explanation:
Just took the test and trying to help you out love.
I hope this helps you
5 1/2=5.2+1/2=11/2
3.11/2
33/2
15 3/2
16,5
