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enot [183]
4 years ago
11

A project has an initial cost of $40,000, expected net cash inflows of $10,000 per year for 8 years, and a cost of capital of 14

%. What is the project's NPV? (Hint: Begin by constructing a time line.) Do not round intermediate calculations. Round your answer to the nearest cent.
Mathematics
1 answer:
ryzh [129]4 years ago
7 0

Answer:

50k

Step-by-step explanation:

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If x=3 y=-5 and z=-2 what is 90xyz ➗xy? PEMDAS PLEASE HELP! :(
garri49 [273]

Step-by-step explanation:

90×3×-5×-2/3×-5

2700/-15

-180

3 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Find the slope in (-2,8) and (1,6)
Salsk061 [2.6K]

Formula for slope: \frac{y2 - y1}{x2 - x1}

y₂: 6

y₁: 8

x₂: 1

x₁: -2

Plug them into the slope equation:

\frac{6 - 8}{1 - (-2)}

--> \frac{-2}{1 + 2}

---> -\frac{2}{3}

The slope is -\frac{2}{3}.

8 0
3 years ago
Read 2 more answers
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
Ray LN is the perpendicular bisector of segment JK.
scoray [572]

Answer:

ok i think "kp" is 17x but i am not 100% sure

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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