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4 years ago

Aniya went golfing. She scored a -2 on the first hole, -2 on the second hole, and 1 on the third hole.

Mathematics

1 answer:

Nookie1986 [14]4 years ago

3 0

Answer:

-3

Step-by-step explanation:

just add it all together i guess

(-2)+(-2)+1=(-3)

score:-3

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The ratio of teachers needs to be 1:30. If there were 120 students, how many teachers would be needed?

mezya [45]

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

4 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

3,497,109.0 plus 6,723.97

Mashutka [201]

3,503,832.97 hope this helps! :)

5 0

3 years ago

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Ezra works two summer jobs to save for a laptop that costs at least $1100. He charges $15/hr to mow lawns and $10/hr to walk dog

LiRa [457]

$\\
\text{Ezra works two summer jobs to save for a laptop that costs at least }\$1100\\
\\
\text{also given that he charges 15 dollars per hour to mow lawns and }\\
\text{10 dollars per hour to walk dogs.}\\
\\
\text{so if he mow lawns for x hours and walk the dogs for y hours in summer,}\\
\text{then the inequality that modeles this data is}\\
\\
15x+10 y \geq 1100$

$\text{now suppose Ezra decides to also spend more than }\$80 \text{ on a printer,}\\
\text{so the total expences he want for laptop and printer is}=1100+80=1180\\
\\
\text{so now the inequality becomes: }$

15 x+10 y >1180

6 0

3 years ago

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NEED HELP ASAP!!! I'LL GIVE BRAINLIEST FOR THE BRAINLIEST ANSWER!!!

boyakko [2]

Answer: 7638373

Step-by-step explanation:

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3 years ago

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